Chemistry reactions and mechanisms
#1
Posted 08 June 2006 - 02:48 PM
I think the general equation is something like:
R-CH2-OH + H+ <--> R-CH2-+OH2 <--> (Br-) R-CH2-Br + H2O
No idea about the mechanisms though.
Regards
PYRODUDE!!!
#2
Posted 08 June 2006 - 03:31 PM
Basic SN2 reaction
A lone pair from the oxygen in the alcohol group donates an electron to an H+ ion (acid solution) (Technically it'll be a H30+ ion that decomposes to give a water molecule as well) to form a dative bond and results in the -OH2+ group, which is a good leaving group.
Next the Bromine ion (Br-) donates an electron into the carbon atom which is joined to the -OH2+ group to form the SN2 intermediate. (The Br ion will have to go in via a Lewis acid like Aluminium tribromide for example.)
Next / simultaneously, an electron from the carbon - Oxygen bond jumps over onto the carbon to release a neutral H20 Molecule and the bromobutane.
I think both the butane chemicals will be liquid at room temp & pressure, so no problems there.
And you'll need the Lewis acid catalyst or you'll be going nowhere fast.
I think that sums it all up, but feel free to ask if some parts don't make sense.
What do you want bromobutane for anyway? Other than a precursor for that whatnot-something addition reaction.
#3
Posted 08 June 2006 - 06:42 PM
Next the Bromine ion (Br-) donates an electron into the carbon atom which is joined to the -OH2+ group to form the SN2 intermediate. (The Br ion will have to go in via a Lewis acid like Aluminium tribromide for example.)
Just one thing, in Sn2 there is no intermediate formed- it uses a transition state - a minor point, but just the sort of thing that loses a mark in an exam!
#4
Posted 09 June 2006 - 03:04 PM
Crap, I've been out of Uni for a year with RSI, let's see if I can remember this...
Basic SN2 reaction
A lone pair from the oxygen in the alcohol group donates an electron to an H+ ion (acid solution) (Technically it'll be a H30+ ion that decomposes to give a water molecule as well) to form a dative bond and results in the -OH2+ group, which is a good leaving group.
Next the Bromine ion (Br-) donates an electron into the carbon atom which is joined to the -OH2+ group to form the SN2 intermediate. (The Br ion will have to go in via a Lewis acid like Aluminium tribromide for example.)
Next / simultaneously, an electron from the carbon - Oxygen bond jumps over onto the carbon to release a neutral H20 Molecule and the bromobutane.
I think both the butane chemicals will be liquid at room temp & pressure, so no problems there.
And you'll need the Lewis acid catalyst or you'll be going nowhere fast.
I think that sums it all up, but feel free to ask if some parts don't make sense.
What do you want bromobutane for anyway? Other than a precursor for that whatnot-something addition reaction.
Thanks, my uncle explained most of it to me. Cheers, I just wanted to know.
#5
Posted 13 June 2006 - 03:27 PM
Ok, synthesis of 1-Ethoxybutane with sodium metal, ethanol and 1-Bromobutane (this is what I needed it for from the first reaction).
Its Sn2 again isn't it.
Synthesis of Dibenzalacetone via aldol reaction with ethanol, benzaldehyde, acetone, water and sodium hydroxide. I have the overall equation for this, but it has phenol rings and stuff so its a bit hard to write in a post.. Need the mechanism again, which I think is pretty long..
Help would be very much appreciated.
Regards
#6
Posted 13 June 2006 - 07:48 PM
#7
Posted 13 June 2006 - 07:53 PM
#8
Posted 13 June 2006 - 08:40 PM
#9
Posted 13 June 2006 - 09:43 PM
But it has been *cough* years since I saw an organic lab.
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