115 replies to this topic

[Gor]

Recently got some BIG balloons

When blown up they are bigger than me. Full of H2 they give a hell of a pull.

Lit they are very nice.

[Stuart]

Lit they are very nice.

With H2 in them I bet they are

Stuart

[burrelly]

biggest fireball i have done is a gallon of petrol with a very large maroon to set it off

[willd]

where do you get your H2 do you make it

[lord_dranack]

I normaly use zinc + DILUTE hydrochloric acid

[willd]

i have heard of that method how much do you need to use to get a desent amount

[PanMaster]

EASY, add aluminium foil waste to caustic soda for dirt cheap H2

[Stuart]

2Al + 2NaOH + 6H2O = 3H2 + (2Na+) + 2Al(OH)4-

[PanMaster]

what on earth is that???

2Al + 6NaOH +6H20 ==> 6NaAlO2 + 9H2

[Stuart]

I checked with my dad and he said that it would form a positive sodium ion and a negative aluminium hydroxide ion. After that both ions would bond to form Sodium Aluminium Hydroxide. And anyway, it probably wont form NaAlO2 as the O2 bit is too reactive

Stuart

Edited by Stuart, 07 November 2003 - 04:38 PM.

[Gor]

Sure, but to get enough pressure to blow up a big balloon I just get a cylinder filled from BOC. You need a proper regualtor though which is expensive.

Chemical reactions can be fun to get an instant flame. Calcium carbide in water is fun. If you don't know what you are doing take care as it is very reactive.

[Stuart]

2Al + 2NaOH + 6H2O --> NaAl(OH)4 + 3H2
Ar/Mr 26.982 + 39.9984 + 18.0178 --> 118.0056 + 2.0188
No Moles(n) 2 + 2 + 6 --> 1 + 3
Total Masses 53.964 + 79.9968 + 108.1068--> 118.0056 + 6.0564

Therefore, If we have

53.964 grams of Aluminium and
79.9968 grams of Sodium Hydroxide and
108.1068 grams of Water

We would get

118.0056 grams of Sodium Aluminium Hydroxide and
6.0564 grams of Hydrogen
---------------------------------------------------
If we then use the equation n=v/22400cm3

v=n*22400cm3

v=3*22400cm3

v=67200cm3

Therefore we get 67.2 liters of Hydrogen gas at STP using the equation and values above


Stuart

[PanMaster]

PV=nTr

P=pressure (Nm) V=volume (m3) n = no of moles T=temperature (K) r =8.31

V = nTrP-1

6x289x8.31/105

=137 (m3) of hydrogen from 6 grams or moles

[Stuart]

Is it illegal to synthesize Hydrogen?


Stuart

[PanMaster]

if you plan to purify the deutrium isotopes for building thermonuclear weapons, then yes it is